WAEC 2022 · Paper 1 · Q22

The table shows the distribution of the distance (in km) covered by 40 hunters while hunting.

Distance (km) 3 4 5 6 7 8
Frequency 5 4 xx 9 2x2x 1

If a hunter is selected at random, find the probability that the hunter covered at least 6 km.

Worked solution (try it first)
  1. The frequencies add up to 40: 5+4+x+9+2x+1=405 + 4 + x + 9 + 2x + 1 = 40, so 3x+19=403x + 19 = 40 and x=7x = 7.
  2. At least 6 km means 6, 7 or 8 km: 9+2(7)+1=249 + 2(7) + 1 = 24 hunters.
  3. So the probability is 2440=35\dfrac{24}{40} = \dfrac{3}{5}, option A.

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