WAEC 2022 · Paper 1 · Q27

A body of mass 18 kg moving with velocity 4 m s−14\text{ m s}^{-1} collides with another body of mass 6 kg moving in the opposite direction with velocity 10 m s−110\text{ m s}^{-1}. If they stick together after collision, find their common velocity.

Worked solution (try it first)
  1. Take the direction of the 18 kg body as positive.
  2. The total momentum before is 18(4)+6(−10)=72−60=1218(4) + 6(-10) = 72 - 60 = 12 kg m/s.
  3. Momentum is conserved and the bodies move together with mass 18+6=2418 + 6 = 24 kg, so 24v=1224v = 12.
  4. So v=12 m s−1v = \frac12\text{ m s}^{-1}, option A.

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