WAEC 2022 · Paper 2 · Q1

A binary operation ∗* is defined on the set T={−2,−1,1,2}T = \{-2, -1, 1, 2\} by p∗q=p2+2pq−q2p * q = p^2 + 2pq - q^2, where p,q∈Tp, q \in T.

  1. (a)

    Copy and complete the table.

    ∗* −2-2 −1-1 11 22
    −2-2 77 −8-8
    −1-1 22 −2-2
    11 −7-7 11
    22 −1-1
    Model answer
    ∗* −2-2 −1-1 11 22
    −2-2 88 77 −1-1 −8-8
    −1-1 11 22 −2-2 −7-7
    11 −7-7 −2-2 22 11
    22 −8-8 −1-1 77 88

    Each entry is p2+2pq−q2p^2 + 2pq - q^2 with pp from the row and qq from the column; for example 2∗1=4+4−1=72 * 1 = 4 + 4 - 1 = 7.

  2. (b)

    Using the table in (a), find the value of pp such that (−2∗p)∗2=−7(-2 * p) * 2 = -7.

Worked solution (try it first)

(a)

  1. Put the row heading in for pp and the column heading in for qq in p2+2pq−q2p^2 + 2pq - q^2.
  2. Row −2-2: 88, 77, −1-1, −8-8.
  3. For example (−2)∗(−2)=4+8−4=8(-2) * (-2) = 4 + 8 - 4 = 8.
  4. Row −1-1: 11, 22, −2-2, −7-7.
  5. For example (−1)∗2=1−4−4=−7(-1) * 2 = 1 - 4 - 4 = -7.
  6. Row 11: −7-7, −2-2, 22, 11.
  7. Row 22: −8-8, −1-1, 77, 88.

(b)

  1. Let x=−2∗px = -2 * p.
  2. Then x∗2=−7x * 2 = -7: in the column under 2, −7-7 is in the row of −1-1, so x=−1x = -1.
  3. Now −2∗p=−1-2 * p = -1: in the row of −2-2, −1-1 is under 11, so p=1p = 1.

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