WAEC 2022 · Paper 2 · Q15

The vectors 6i+8j6\mathbf i + 8\mathbf j and 8i−6j8\mathbf i - 6\mathbf j are parallel to OP→\overrightarrow{OP} and OQ→\overrightarrow{OQ} respectively. If the magnitudes of OP→\overrightarrow{OP} and OQ→\overrightarrow{OQ} are 80 units and 120 units respectively, express:

  1. (a)

    OP→\overrightarrow{OP} and OQ→\overrightarrow{OQ} in terms of i\mathbf i and j\mathbf j;

    Show the answer

    OP→=48i+64j\overrightarrow{OP} = 48\mathbf i + 64\mathbf j, OQ→=96i−72j\overrightarrow{OQ} = 96\mathbf i - 72\mathbf j

  2. (b)

    ∣PQ→∣|\overrightarrow{PQ}| in the form ckc\sqrt k, where cc and kk are constants.

Worked solution (try it first)

(a)

  1. ∣6i+8j∣=10|6\mathbf i + 8\mathbf j| = 10, so OP→=8010(6i+8j)\overrightarrow{OP} = \frac{80}{10}(6\mathbf i + 8\mathbf j)
    =48i+64j= 48\mathbf i + 64\mathbf j.
  2. ∣8i−6j∣=10|8\mathbf i - 6\mathbf j| = 10, so OQ→=12010(8i−6j)\overrightarrow{OQ} = \frac{120}{10}(8\mathbf i - 6\mathbf j)
    =96i−72j= 96\mathbf i - 72\mathbf j.

(b)

  1. PQ→=OQ→−OP→\overrightarrow{PQ} = \overrightarrow{OQ} - \overrightarrow{OP}
    =48i−136j= 48\mathbf i - 136\mathbf j.
  2. ∣PQ→∣=2304+18 496|\overrightarrow{PQ}| = \sqrt{2304 + 18\,496}
    =20 800= \sqrt{20\,800}.
  3. 20 800=1600×1320\,800 = 1600 \times 13, so ∣PQ→∣=4013|\overrightarrow{PQ}| = 40\sqrt{13}.

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