WAEC 2023 · Paper 1 · Q34

Evaluate: ∫(2x+1)3 dx\displaystyle\int (2x + 1)^3\,dx.

Worked solution (try it first)
  1. Raise the power by one and divide by the new power: (2x+1)44\dfrac{(2x + 1)^4}{4}.
  2. Divide also by 2, the coefficient of xx inside the bracket: (2x+1)44×2\dfrac{(2x + 1)^4}{4 \times 2}.
  3. So the integral is 18(2x+1)4+k\frac{1}{8}(2x + 1)^4 + k, option D.

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