WAEC 2023 · Paper 1 · Q6

In how many ways can a committee of 3 women and 2 men be chosen from a group of 7 men and 5 women?

Worked solution (try it first)

Choose the 3 women from 5: $^{5}C_3 = 10$ ways.
Choose the 2 men from 7: $^{7}C_2 = 21$ ways.
Each choice of women goes with each choice of men, so multiply: $10 \times 21 = 210$ , option D.