A particle is projected at an angle of 42∘ with a velocity of 68 m s−1. Calculate, correct to one decimal place, the: (i) greatest height travelled; (ii) time of flight; (iii) horizontal range travelled. [g=10 m s−2] Enter the three values.
(b)
A non-uniform beam PQ of length 15 m and weight 120 N rests horizontally on supports at P and Q. If the centre of gravity of the beam is 3.5 m from Q, find the reaction at Q.
Worked solution (try it first)
(a)(i)
H=2gu2sin2θ
=20682sin242∘
≈103.5 m.
(ii)
T=g2usinθ
=10136sin42∘
≈9.1 s.
(iii)
R=gu2sin2θ
=104624sin84∘
≈459.9 m.
(b)
The weight acts at the centre of gravity, 15−3.5=11.5 m from P.
Moments about P: 15RQ=120×11.5=1380, so RQ=92 N.