WAEC 2008 · Paper 2 · Q1

  1. (a)

    If x:y=2:3x : y = 2 : 3, evaluate x2−y2y2+x2\dfrac{x^2 - y^2}{y^2 + x^2}.

  2. (b)

    A man on the same level ground with a tree stands at a distance of 12.82 m12.82\text{ m} from the foot of the tree. He observes the angle of elevation of the top of the tree as 52∘52^\circ. If the man is 1.24 m1.24\text{ m} tall, calculate, correct to two decimal places, the height of the tree.

Worked solution (try it first)

(a)

  1. A ratio of 2:32 : 3 means x=2kx = 2k and y=3ky = 3k for some number kk.
  2. Put these in: x2−y2=4k2−9k2=−5k2x^2 - y^2 = 4k^2 - 9k^2 = -5k^2 and y2+x2=9k2+4k2=13k2y^2 + x^2 = 9k^2 + 4k^2 = 13k^2.
  3. Divide, and k2k^2 cancels: the value is −513-\frac{5}{13}.

(b)

  1. Draw the right-angled triangle from the man's eye: the horizontal side is 12.82 m12.82\text{ m} and the angle at his eye is 52∘52^\circ.
  2. The height of the tree above his eye is h=12.82tan⁡52∘h = 12.82 \tan 52^\circ
    =12.82×1.2799= 12.82 \times 1.2799
    =16.409 m= 16.409\text{ m}.
  3. Add the man's height, because the angle is measured from his eye: 16.409+1.24=17.64916.409 + 1.24 = 17.649.
  4. The tree is 17.65 m17.65\text{ m} tall, to two decimal places.

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