WAEC 2008 · Paper 2 · Q12

  1. (a)

    Copy and complete the table of values for y=3sin⁡x+2cos⁡xy = 3\sin x + 2\cos x for 0∘≤x≤360∘0^\circ \le x \le 360^\circ.

    xx 0∘0^\circ 60∘60^\circ 120∘120^\circ 180∘180^\circ 240∘240^\circ 300∘300^\circ 360∘360^\circ
    yy 2.002.00 2.002.00
    Model answer
    xx 0∘0^\circ 60∘60^\circ 120∘120^\circ 180∘180^\circ 240∘240^\circ 300∘300^\circ 360∘360^\circ
    yy 2.002.00 3.603.60 1.601.60 −2.00-2.00 −3.60-3.60 −1.60-1.60 2.002.00

    The values from 180∘180^\circ to 360∘360^\circ are the negatives of those from 0∘0^\circ to 180∘180^\circ, since sin⁡\sin and cos⁡\cos both change sign after 180∘180^\circ.

  2. (b)

    Using a scale of 2 cm to 60∘60^\circ on the xx-axis and 2 cm to 1 unit on the yy-axis, draw the graph of y=3sin⁡x+2cos⁡xy = 3\sin x + 2\cos x for 0∘≤x≤360∘0^\circ \le x \le 360^\circ.

    Model answer

    Plot (0∘,2.00)(0^\circ, 2.00), (60∘,3.60)(60^\circ, 3.60), (120∘,1.60)(120^\circ, 1.60), (180∘,−2.00)(180^\circ, -2.00), (240∘,−3.60)(240^\circ, -3.60), (300∘,−1.60)(300^\circ, -1.60), (360∘,2.00)(360^\circ, 2.00) and join them with one smooth wave. The curve peaks at about 3.63.6 near x=56∘x = 56^\circ, crosses the xx-axis near 146∘146^\circ and 326∘326^\circ, and is lowest, about −3.6-3.6, near 236∘236^\circ.

  3. (c)

    Use your graph to solve the equation 3sin⁡x+2cos⁡x=1.53\sin x + 2\cos x = 1.5.

    Separate values with commas, e.g. 3, −2

  4. (d)

    Find the range of values of xx for which 3sin⁡x+2cos⁡x<−13\sin x + 2\cos x < -1.

    Separate values with commas, e.g. 3, −2

Try it on a graph

x in degrees. The lines y = 1.5 and y = -1 give (c) and (d).

Worked solution (try it first)

(a)

  1. Work out each value in degree mode.
  2. For example, at 60∘60^\circ: 3(0.8660)+2(0.5)=3.603(0.8660) + 2(0.5) = 3.60.
  3. At 120∘120^\circ: 3(0.8660)+2(−0.5)=1.603(0.8660) + 2(-0.5) = 1.60.
  4. At 180∘180^\circ: 3(0)+2(−1)=−2.003(0) + 2(-1) = -2.00.
  5. At 240∘240^\circ: 3(−0.8660)+2(−0.5)=−3.603(-0.8660) + 2(-0.5) = -3.60.
  6. At 300∘300^\circ: 3(−0.8660)+2(0.5)=−1.603(-0.8660) + 2(0.5) = -1.60.
  7. The completed row is 2.00,3.60,1.60,−2.00,−3.60,−1.60,2.002.00, 3.60, 1.60, -2.00, -3.60, -1.60, 2.00.

(b)

  1. Plot the seven points with the scales given and join them with a smooth curve.

(c)

  1. Draw the line y=1.5y = 1.5 and read down from where it meets the curve: x≈122∘x \approx 122^\circ and x≈351∘x \approx 351^\circ.

(d)

  1. Draw the line y=−1y = -1.
  2. The curve is below it between the two crossing points, about 162∘162^\circ and 310∘310^\circ.
  3. So 162∘<x<310∘162^\circ < x < 310^\circ.

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