WAEC 2009 · Paper 2 · Q6

  1. (a)

    If log⁡5=0.6990\log 5 = 0.6990, log⁡7=0.8451\log 7 = 0.8451 and log⁡8=0.9031\log 8 = 0.9031, evaluate log⁡(35×4940÷56)\log\left(\dfrac{35 \times 49}{40 \div 56}\right).

  2. (b)(i)

    For a musical show, xx children were present. There were 60 more adults than children. An adult paid D5 and a child D2. If a total of D1280 was collected, calculate the value of xx.

  3. (b)(ii)

    Calculate the ratio of the number of children to the number of adults.

  4. (b)(iii)

    Calculate the average amount paid per person.

  5. (b)(iv)

    Calculate the percentage profit if the organisers spent D720 on the show.

Worked solution (try it first)

(a)

  1. Write each number with factors 5, 7 and 8: 35=5×735 = 5 \times 7, 49=7×749 = 7 \times 7, 40=5×840 = 5 \times 8, 56=7×856 = 7 \times 8.
  2. Dividing by 40÷5640 \div 56 is multiplying by 5640\frac{56}{40}: the number is 5×7×7×7×7×85×8=74\frac{5 \times 7 \times 7 \times 7 \times 7 \times 8}{5 \times 8} = 7^4.
  3. So the log is 4log⁡7=4×0.8451=3.38044\log 7 = 4 \times 0.8451 = 3.3804.

(b)(i)

  1. Adults =x+60= x + 60.
  2. Money collected: 2x+5(x+60)=12802x + 5(x + 60) = 1280.
  3. Expand: 7x+300=12807x + 300 = 1280, so 7x=9807x = 980 and x=140x = 140.

(ii)

  1. There were 140 children and 200 adults: the ratio is 140:200=7:10140 : 200 = 7 : 10.

(iii)

  1. Number of people =140+200=340= 140 + 200 = 340.
  2. Average =1280340=3.76= \frac{1280}{340} = 3.76, so D3.76 per person.

(iv)

  1. Profit =1280−720=560= 1280 - 720 = 560, so the profit is D560.
  2. Percentage profit =560720×100=77.8%= \frac{560}{720} \times 100 = 77.8\%.

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