WAEC 2009 · Paper 2 · Q2

  1. (a)

    Solve the equation 4x−13−3x−12=5−2x4\dfrac{4x - 1}{3} - \dfrac{3x - 1}{2} = \dfrac{5 - 2x}{4}.

  2. (b)

    From a shop, Kofi bought 2 singlets and 3 shirts for GH¢31.00, while Kwasi bought 3 singlets and 2 shirts for GH¢29.00. How much will Yaw pay for one singlet and one shirt bought from the same shop?

Worked solution (try it first)

(a)

  1. Multiply every term by the LCM 12: 4(4x−1)−6(3x−1)=3(5−2x)4(4x - 1) - 6(3x - 1) = 3(5 - 2x).
  2. Expand: 16x−4−18x+6=15−6x16x - 4 - 18x + 6 = 15 - 6x.
  3. Simplify the left: −2x+2=15−6x-2x + 2 = 15 - 6x.
  4. Collect terms: 4x=134x = 13, so x=134=314x = \frac{13}{4} = 3\frac14.

(b)

  1. Let a singlet cost GH¢xx and a shirt GH¢yy: 2x+3y=312x + 3y = 31 and 3x+2y=293x + 2y = 29.
  2. Add the equations: 5x+5y=605x + 5y = 60, so x+y=12x + y = 12.
  3. (Solving fully gives x=5x = 5 and y=7y = 7.) Yaw pays GH¢12.00.

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