WAEC 2011 · Paper 2 · Q6✱

In a class of 40 students, 18 passed Mathematics, 19 passed Accounts, 16 passed Economics, 5 Mathematics and Accounts only, 6 Mathematics only, 9 Accounts only, 2 Accounts and Economics only. Each student offered at least one of the subjects.

  1. (a)

    How many students failed in all the subjects?

  2. (b)

    Find the percentage of the students who failed both Economics and Mathematics.

  3. (c)

    Calculate the probability that a student selected at random failed in Accounts.

Worked solution (try it first)
  1. Draw a Venn diagram with three overlapping circles, M, A and E, inside a rectangle for the 40 students.
  2. Fill in the regions you are given: M only 6, A only 9, M and A only 5, A and E only 2.
  3. Let the centre (all three) be xx.
  4. Find the centre. Accounts has 19 students: 9+5+2+x=199 + 5 + 2 + x = 19, so x=3x = 3.
  5. M and E only: Mathematics has 18: 6+5+3+(M and E only)=186 + 5 + 3 + (\text{M and E only}) = 18, so M and E only is 4.
  6. E only: Economics has 16: 4+3+2+(E only)=164 + 3 + 2 + (\text{E only}) = 16, so E only is 7.

(a)

  1. The students who passed at least one subject are 6+5+9+3+4+2+7=366 + 5 + 9 + 3 + 4 + 2 + 7 = 36.
  2. So 40−36=440 - 36 = 4 students failed all three.

(b)

  1. Failing both means passing neither.
  2. Passed Mathematics or Economics (or both): 18+16−(4+3)=2718 + 16 - (4 + 3) = 27.
  3. So 40−27=1340 - 27 = 13 failed both, and 1340×100=3212%\frac{13}{40} \times 100 = 32\frac12\%.

(c)

  1. 19 passed Accounts, so 40−19=2140 - 19 = 21 failed it.
  2. P(failed Accounts)=2140P(\text{failed Accounts}) = \frac{21}{40}.

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