WAEC 2012 · Paper 2 · Q4

  1. (a)

    A box contains 40 identical discs which are either red or white. If the probability of picking a red disc is 14\frac14, calculate the number of: (i) white discs; (ii) red discs that should be added such that the probability of picking a red disc will be 13\frac13.

    Separate values with commas, e.g. 3, −2

  2. (b)

    A salesman bought some plates at ₦50.00 each. If he sold all of them for ₦600 and made a profit of 20%20\% on the transaction, how many plates did he buy?

Worked solution (try it first)

(a)(i)

  1. P(red)=red discs40P(\text{red}) = \frac{\text{red discs}}{40}
    =14= \frac14, so there are 14×40=10\frac14 \times 40 = 10 red discs and 40−10=3040 - 10 = 30 white discs.

(ii)

  1. Add rr red discs.
  2. Then there are 10+r10 + r red discs out of 40+r40 + r altogether, and we want 10+r40+r=13\frac{10 + r}{40 + r} = \frac13.
  3. Cross-multiply: 3(10+r)=40+r3(10 + r) = 40 + r, so 30+3r=40+r30 + 3r = 40 + r, 2r=102r = 10 and r=5r = 5.
  4. Check: 1545=13\frac{15}{45} = \frac13.

(b)

  1. A 20%20\% profit means the selling price is 120%120\% of the cost price.
  2. So 1.2×1.2 \times cost == ₦600, and the cost is ₦600 ÷1.2=\div 1.2 = ₦500.
  3. At ₦50.00 each, he bought 50050=10\frac{500}{50} = 10 plates.

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