WAEC 2013 · Paper 2 · Q6

  1. (a)

    Two positive whole numbers PP and qq are such that PP is greater than qq and their sum is equal to three times their difference. (i) Express PP in terms of qq. (ii) Hence, evaluate P2+q2Pq\dfrac{P^2 + q^2}{Pq}.

  2. (b)

    A man sold 100 articles at 25 for ₦66.00 and made a gain of 32%32\%. Calculate his gain or loss percent if he sold them at 20 for ₦50.00.

Worked solution (try it first)

(a)(i)

  1. Their sum is three times their difference: P+q=3(P−q)P + q = 3(P - q).
  2. Expand: P+q=3P−3qP + q = 3P - 3q.
  3. So 4q=2P4q = 2P and P=2qP = 2q.

(ii)

  1. Substitute P=2qP = 2q: P2+q2Pq=4q2+q22q×q\frac{P^2 + q^2}{Pq} = \frac{4q^2 + q^2}{2q \times q}
    =5q22q2= \frac{5q^2}{2q^2}
    =52= \frac52
    =212= 2\frac12.

(b)

  1. At 25 for ₦66, the 100 articles sold for 10025×66=₦264\frac{100}{25} \times 66 = ₦264.
  2. That was a 32%32\% gain, so 264=1.32×264 = 1.32 \times cost price, and the cost price is 2641.32=₦200\frac{264}{1.32} = ₦200.
  3. At 20 for ₦50 they would sell for 10020×50=₦250\frac{100}{20} \times 50 = ₦250.
  4. Gain =250−200=₦50= 250 - 200 = ₦50, which is 50200×100%=25%\frac{50}{200} \times 100\% = 25\%.
  5. It is a gain of 25%25\%.

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