WAEC 2014 · Paper 2 · Q3

  1. (a)

    Solve the simultaneous equations 1x+1y=5\dfrac1x + \dfrac1y = 5 and 1y−1x=1\dfrac1y - \dfrac1x = 1.

    Separate values with commas, e.g. 3, −2

  2. (b)

    A man drives from Ibadan to Oyo, a distance of 48 km48\text{ km}, in 45 minutes. If he drives at 72 km/h72\text{ km/h} where the surface is good and 48 km/h48\text{ km/h} where it is bad, find the number of kilometres of good surface.

Worked solution (try it first)

(a)

  1. Treat 1x\frac1x and 1y\frac1y as the unknowns.
  2. Adding the equations, the 1x\frac1x terms cancel: 2y=6\frac2y = 6, so 1y=3\frac1y = 3 and y=13y = \frac13.
  3. Taking the second equation from the first: 2x=4\frac2x = 4, so 1x=2\frac1x = 2 and x=12x = \frac12.

(b)

  1. Let the good surface be xx km.
  2. The bad surface is then (48−x)(48 - x) km.
  3. Time =distancespeed= \frac{\text{distance}}{\text{speed}}, so the two times are x72\frac{x}{72} and 48−x48\frac{48 - x}{48} hours.
  4. The whole journey takes 45 minutes =34= \frac34 hour: x72+48−x48=34\frac{x}{72} + \frac{48 - x}{48} = \frac34.
  5. Multiply every term by 144: 2x+3(48−x)=1082x + 3(48 - x) = 108.
  6. So 2x+144−3x=1082x + 144 - 3x = 108, −x=−36-x = -36 and x=36x = 36.
  7. There are 36 km of good surface.

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