WAEC 2014 · Paper 2 · Q4

  1. (a)

    Without using tables or a calculator, evaluate log⁡10(7510)−2log⁡10(59)+log⁡10(100243)\log_{10}\left(\frac{75}{10}\right) - 2\log_{10}\left(\frac59\right) + \log_{10}\left(\frac{100}{243}\right).

  2. (b)

    Given that X={x:10≤x<15}X = \{x : 10 \le x < 15\} and Y={even numbers<18}Y = \{\text{even numbers} < 18\} are subsets of U={10,11,12,…,20}U = \{10, 11, 12, \ldots, 20\}, find: (i) X∩YX \cap Y; (ii) n(X′∩Y)n(X' \cap Y).

Worked solution (try it first)

(a)

  1. Move the 2 inside as a power: 2log⁡1059=log⁡1025812\log_{10}\frac59 = \log_{10}\frac{25}{81}.
  2. Then combine: log⁡10(7510×100243÷2581)\log_{10}\left(\frac{75}{10} \times \frac{100}{243} \div \frac{25}{81}\right).
  3. Simplify: 7510×100243×8125=75×100×8110×243×25\frac{75}{10} \times \frac{100}{243} \times \frac{81}{25} = \frac{75 \times 100 \times 81}{10 \times 243 \times 25}
    =10= 10.
  4. So the answer is log⁡1010=1\log_{10} 10 = 1.

(b)

  1. X={10,11,12,13,14}X = \{10, 11, 12, 13, 14\} and YY (even numbers in UU less than 18) ={10,12,14,16}= \{10, 12, 14, 16\}.

(i)

  1. X∩Y={10,12,14}X \cap Y = \{10, 12, 14\}.

(ii)

  1. X′={15,16,17,18,19,20}X' = \{15, 16, 17, 18, 19, 20\}, so X′∩Y={16}X' \cap Y = \{16\} and n(X′∩Y)=1n(X' \cap Y) = 1.

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