WAEC 2016 · Paper 2 · Q2

  1. (a)

    If mm−y+2=ry+r−1\dfrac{m}{m - y + 2} = \dfrac{r}{y + r - 1}, make yy the subject of the equation.

  2. (b)

    In a school, 60%60\% of the girls and 70%70\% of the boys own a bicycle. If a boy and a girl are selected at random from the school, find the probability that only one of them owns a bicycle.

Worked solution (try it first)

(a)

  1. Cross-multiply: m(y+r−1)=r(m−y+2)m(y + r - 1) = r(m - y + 2).
  2. Expand: my+mr−m=mr−ry+2rmy + mr - m = mr - ry + 2r.
  3. The mrmr terms cancel: my−m=−ry+2rmy - m = -ry + 2r.
  4. Collect the yy terms on the left: my+ry=m+2rmy + ry = m + 2r.
  5. Take out yy: y(m+r)=m+2ry(m + r) = m + 2r.
  6. So y=m+2rm+ry = \frac{m + 2r}{m + r}.

(b)

  1. A girl owns a bicycle with probability 0.60.6 (so doesn't with 0.40.4).
  2. A boy with 0.70.7 (doesn't with 0.30.3). "Only one of them" happens in two ways.
  3. The girl owns one and the boy doesn't: 0.6×0.3=0.180.6 \times 0.3 = 0.18.
  4. The boy owns one and the girl doesn't: 0.7×0.4=0.280.7 \times 0.4 = 0.28.
  5. Add the two ways: 0.18+0.28=0.46=23500.18 + 0.28 = 0.46 = \frac{23}{50}.

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