WAEC 2018 · Paper 2 · Q10
- (a)
Copy and complete the table of values for , .
Model answer
0° 30° 60° 90° 120° 150° 180° 210° 240° 270° 300° 2.00 1.23 0.13 −1.00 −1.87 −2.23 −2.00 −1.23 −0.13 1.00 1.87 For example, at : (2 d.p.).
- (b)
Using scales of 2 cm to on the -axis and 2 cm to 1 unit on the -axis, draw the graph of for .
Model answer
Plot every point from the table, then join them with one smooth curve (not straight lines between points). Scale: 2 cm to , 2 cm to 1 unit.
For (c): (i) draw : it meets the curve at and . (ii) means , i.e. : read where the curve crosses the -axis, and .
- (c)(i)
Use the graph to find the values of for which .
- (c)(ii)
Use the graph to find the values of for which .
Try it on a graph
x in degrees. The line y = 1 gives (c)(i); the x-axis gives (c)(ii).
Worked solution (try it first)
(a)
- In degree mode, to 2 decimal places as in the table.
- For example, : .
- : .
- The full row is .
(b)
- Plot the points with the scales given and join them with a smooth curve.
(c)(i)
- Draw the line and read down from where it crosses the curve: and .
(ii)
- Rearrange so it matches the graph: means , so , which is .
- So read where the curve crosses the -axis: and .