WAEC 2018 · Paper 2 · Q12✱✱

  1. (a)

    Mr John paid ₦8,400.00 for ₦1.00 ordinary shares of a company which sold at ₦2.50 per share. If a dividend was declared at 25 kobo per share, how much dividend did he get?

  2. (b)

    Using the method of completing the square, solve 1−xx+x1−x=52\dfrac{1 - x}{x} + \dfrac{x}{1 - x} = \dfrac52.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. The shares cost ₦2.50 each, so ₦8,400 buys 84002.50=3360\frac{8400}{2.50} = 3360 shares.
  2. The dividend is 25 kobo (₦0.25) per share: 3360×0.25=8403360 \times 0.25 = 840, which is ₦840.00.

(b)

  1. Multiply every term by 2x(1−x)2x(1 - x): 2(1−x)2+2x2=5x(1−x)2(1 - x)^2 + 2x^2 = 5x(1 - x).
  2. Expand: 2−4x+2x2+2x2=5x−5x22 - 4x + 2x^2 + 2x^2 = 5x - 5x^2, so 9x2−9x+2=09x^2 - 9x + 2 = 0.
  3. Divide by 9: x2−x=−29x^2 - x = -\frac29.
  4. Add (12)2=14\left(\frac12\right)^2 = \frac14 to both sides: (x−12)2=14−29\left(x - \frac12\right)^2 = \frac14 - \frac29
    =136= \frac{1}{36}.
  5. So x−12=±16x - \frac12 = \pm\frac16, giving x=23x = \frac23 or x=13x = \frac13.

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