WAEC 2019 · Paper 2 · Q12

  1. (a)

    Given that sin⁡y=817\sin y = \frac{8}{17}, find the value of tan⁡y1+2tan⁡y\dfrac{\tan y}{1 + 2\tan y}.

  2. (b)

    An amount of ₦300,000.00 was shared among Otobo, Ada and Adeola. Otobo received ₦60,000.00, Ada received 512\frac{5}{12} of the remainder, while the rest went to Adeola. In what ratio was the money shared?

    Show the answer

    3:5:73 : 5 : 7

Worked solution (try it first)

(a)

  1. sin⁡y=817\sin y = \frac{8}{17}: the adjacent side is 172−82=225=15\sqrt{17^2 - 8^2} = \sqrt{225} = 15, so tan⁡y=815\tan y = \frac{8}{15}.
  2. Then tan⁡y1+2tan⁡y=8151+1615\frac{\tan y}{1 + 2\tan y} = \frac{\frac{8}{15}}{1 + \frac{16}{15}}
    =8153115= \frac{\frac{8}{15}}{\frac{31}{15}}
    =831= \frac{8}{31}.

(b)

  1. After Otobo's ₦60,000, the remainder is ₦240,000.
  2. Ada received 512×240 000=\frac{5}{12} \times 240\,000 = ₦100,000, and Adeola the rest, ₦140,000.
  3. The ratio is 60 000:100 000:140 000=3:5:760\,000 : 100\,000 : 140\,000 = 3 : 5 : 7.

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