WAEC 2019 · Paper 2 · Q3

  1. (a)

    Ali, Musah and Yusif shared ₦420,000.00 in the ratio 3:5:83 : 5 : 8 respectively. Find the sum of Ali's and Yusif's shares.

  2. (b)

    Solve: 2(18)x=32x−12\left(\frac18\right)^x = 32^{x - 1}.

Worked solution (try it first)

(a)

  1. The ratio has 3+5+8=163 + 5 + 8 = 16 parts, so one part is 420 00016=26 250\frac{420\,000}{16} = 26\,250.
  2. Ali gets 3×26 250=₦78,7503 \times 26\,250 = ₦78,750 and Yusif 8×26 250=₦210,0008 \times 26\,250 = ₦210,000.
  3. Together: ₦288,750.

(b)

  1. Write both sides as powers of 2: 2×(2−3)x=21−3x2 \times (2^{-3})^x = 2^{1 - 3x} and 32x−1=25(x−1)=25x−532^{x - 1} = 2^{5(x - 1)} = 2^{5x - 5}.
  2. So 1−3x=5x−51 - 3x = 5x - 5, 8x=68x = 6 and x=34x = \frac34.

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