WAEC 2020 · Paper 1 · Q30

In the diagram, MN∥PQMN \parallel PQ, ∠MNP=2x\angle MNP = 2x and ∠NPQ=(3x−50)∘\angle NPQ = (3x - 50)^\circ. Find the value of ∠NPQ\angle NPQ.

2x°(3x − 50)°MNPQ
Worked solution (try it first)
  1. MN∥PQMN \parallel PQ and ∠MNP\angle MNP, ∠NPQ\angle NPQ are alternate angles, so they are equal: 2x=3x−502x = 3x - 50.
  2. Subtract 2x2x and add 50: x=50x = 50.
  3. So ∠NPQ=3(50)−50=100∘\angle NPQ = 3(50) - 50 = 100^\circ, option D.

Report a problem with this question