WAEC 2020 · Paper 1 · Q5

Express 1+2log⁡1031 + 2\log_{10} 3 in the form log⁡10q\log_{10} q.

Worked solution (try it first)
  1. Write 1 as a log: 1=log⁡10101 = \log_{10} 10.
  2. Move the 2 up as a power: 2log⁡103=log⁡1092\log_{10} 3 = \log_{10} 9.
  3. Adding logs multiplies: log⁡1010+log⁡109=log⁡1090\log_{10} 10 + \log_{10} 9 = \log_{10} 90, option A.

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