WAEC 2020 · Paper 2 · Q1

  1. (a)

    Two fractions have the same denominator, 8. The sum of the two fractions is 12\frac12. If one of the fractions is added to 5 times the other, the result is 2. Find the two fractions.

    Separate values with commas, e.g. 3, −2

  2. (b)

    If a=mg−kv2ma = \dfrac{mg - kv^2}{m}, find, correct to the nearest whole number, the value of vv when a=2.8a = 2.8, m=12m = 12, g=9.8g = 9.8 and k=83k = \frac83.

Worked solution (try it first)

(a)

  1. Let the two fractions be x8\frac x8 and y8\frac y8 (a different letter for each).
  2. Their sum is 12\frac12: x8+y8=12\frac x8 + \frac y8 = \frac12, so x+y=4x + y = 4 (1).
  3. One added to 5 times the other is 2: x8+5y8=2\frac x8 + \frac{5y}{8} = 2, so x+5y=16x + 5y = 16 (2).
  4. Take (1) from (2): 4y=124y = 12, so y=3y = 3 and x=1x = 1.
  5. The fractions are 18\frac18 and 38\frac38.

(b)

  1. First make vv the subject.
  2. Multiply by mm: am=mg−kv2am = mg - kv^2.
  3. Rearrange: kv2=mg−am=m(g−a)kv^2 = mg - am = m(g - a).
  4. So v2=m(g−a)kv^2 = \frac{m(g - a)}{k} and v=m(g−a)kv = \sqrt{\frac{m(g - a)}{k}}.
  5. Substitute: v=12×(9.8−2.8)83v = \sqrt{\frac{12 \times (9.8 - 2.8)}{\frac83}}
    =84×38= \sqrt{\frac{84 \times 3}{8}}
    =31.5= \sqrt{31.5}
    ≈5.61\approx 5.61.
  6. To the nearest whole number, v=6v = 6.

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