WAEC 2021 · Paper 2 · Q3

  1. (a)

    A vertical pole 6 m6\text{ m} high casts a shadow 9 m9\text{ m} long at the same time that a tree casts a shadow 30 m30\text{ m} long. Find the height of the tree.

  2. (b)

    Solve for yy: log⁡(5y−4)=log⁡(y+1)+log⁡4\log(5y - 4) = \log(y + 1) + \log 4.

Worked solution (try it first)

(a)

  1. At the same time of day, heights and shadows are in the same ratio (similar triangles): h30=69\frac{h}{30} = \frac{6}{9}, so h=30×23=20h = 30 \times \frac23 = 20 m.

(b)

  1. Combine the right side: log⁡(y+1)+log⁡4=log⁡4(y+1)\log(y + 1) + \log 4 = \log 4(y + 1).
  2. So log⁡(5y−4)=log⁡(4y+4)\log(5y - 4) = \log(4y + 4), which gives 5y−4=4y+45y - 4 = 4y + 4 and y=8y = 8.
  3. Check: 5y−4=365y - 4 = 36 and y+1=9y + 1 = 9 are positive.

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