QuestionWAECGeneral Maths2022ObjectiveLinear & simultaneous equationsLinear & simultaneous equations
WAEC 2022 · Paper 1 · Q17
Find the value of x such that x1+3x4−6x5+1=0.
Worked solution (try it first)
The LCM of the denominators
x,
3x and
6x is
6x.
Multiply every term by
6x, including the 1:
6+8−5+6x=0.
Collect the numbers:
9+6x=0, so
6x=−9.
Divide by 6:
x=−69=−23, option C.
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