WAEC 2022 · Paper 1 · Q28

A boy 1.4 m1.4\text{ m} tall stood 10 m10\text{ m} away from a tree of height 12 m12\text{ m}. Calculate, correct to the nearest degree, the angle of elevation of the top of the tree from the boy's eyes.

Worked solution (try it first)
  1. Measure from the boy's eyes: the top of the tree is 12−1.4=10.612 - 1.4 = 10.6 m higher, and 10 m away.
  2. So tan⁡θ=10.610=1.06\tan\theta = \frac{10.6}{10} = 1.06.
  3. So θ=tan⁡−11.06≈46.7∘\theta = \tan^{-1}1.06 \approx 46.7^\circ, which is 47∘47^\circ to the nearest degree, option B.

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