WAEC 2022 · Paper 1 · Q30

In the diagram, MNRMNR is a tangent to the circle at NN and ∠NOS=108∘\angle NOS = 108^\circ. Find ∠OSN\angle OSN.

108°ONSMR
Worked solution (try it first)
  1. ON=OSON = OS (radii), so triangle NOSNOS is isosceles and its base angles at NN and SS are equal.
  2. So ∠OSN=180∘−108∘2\angle OSN = \dfrac{180^\circ - 108^\circ}{2}
    =36∘= 36^\circ, option C.
  3. The tangent is not needed.

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