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WAEC 2022 · Paper 1 · Q49

Given that log⁡327=2x+1\log_3 27 = 2x + 1, find the value of xx.

Worked solution (try it first)
  1. 27=3327 = 3^3, so log⁡327=3\log_3 27 = 3.
  2. So 2x+1=32x + 1 = 3.
  3. Subtract 1 and divide by 2: x=1x = 1, option B.

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