QuestionWAECGeneral Maths2022ObjectiveModular arithmeticModular arithmetic
Evaluate 23×54(mod7).
Worked solution (try it first)
Reduce each number:
23=3×7+2, so
23≡2.
54=7×7+5, so
54≡5(mod7).
Multiply the remainders:
2×5=10.
Reduce again:
10=7+3, so
23×54≡3(mod7), option B.
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