WAEC 2022 · Paper 1 · Q5

Evaluate 23×54(mod7)23 \times 54 \pmod 7.

Worked solution (try it first)
  1. Reduce each number: 23=3×7+223 = 3 \times 7 + 2, so 23≡223 \equiv 2.
  2. 54=7×7+554 = 7 \times 7 + 5, so 54≡5(mod7)54 \equiv 5 \pmod 7.
  3. Multiply the remainders: 2×5=102 \times 5 = 10.
  4. Reduce again: 10=7+310 = 7 + 3, so 23×54≡3(mod7)23 \times 54 \equiv 3 \pmod 7, option B.

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