WAEC 2022 · Paper 2 · Q11

Age (years) 1 2 3 4 5 6 7 8 9 10
Number of pupils 12 14 20 45 36 20 23 16 8 6

The table is a frequency distribution of ages of 200 pupils in a school. Find, correct to one decimal place, the:

  1. (a)

    mean;

  2. (b)

    standard deviation of the distribution.

Worked solution (try it first)
  1. Use an assumed mean of 5 years, with d=x−5d = x - 5:
  2. Age xx 1 2 3 4 5 6 7 8 9 10 Total
    ff 12 14 20 45 36 20 23 16 8 6 200
    dd −4-4 −3-3 −2-2 −1-1 0 1 2 3 4 5
    fdfd −48-48 −42-42 −40-40 −45-45 0 20 46 48 32 30 1
    fd2fd^2 192 126 80 45 0 20 92 144 128 150 977

(a)

  1. Mean =5+1200=5.005≈5.0= 5 + \frac{1}{200} = 5.005 \approx 5.0 years.

(b)

  1. Standard deviation =∑fd2∑f−(∑fd∑f)2= \sqrt{\frac{\sum fd^2}{\sum f} - \left(\frac{\sum fd}{\sum f}\right)^2}
    =977200−(1200)2= \sqrt{\frac{977}{200} - \left(\frac{1}{200}\right)^2}
    =4.885= \sqrt{4.885}
    ≈2.2\approx 2.2 years.

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