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WAEC 2023 · Paper 1 · Q22

A line LL passing through the point (6,−13)(6, -13) is parallel to the line which passes through (7,4)(7, 4) and (−3,9)(-3, 9). Find the equation of the line LL.

Worked solution (try it first)
  1. Gradient of the given line: 9−4−3−7=5−10\dfrac{9 - 4}{-3 - 7} = \frac{5}{-10}
    =−12= -\frac12.
  2. Parallel lines share it.
  3. Through (6,−13)(6, -13): y+13=−12(x−6)y + 13 = -\frac12(x - 6), so y+13=−12x+3y + 13 = -\frac12x + 3.
  4. Subtract 13 from both sides: y=−12x−10y = -\frac12x - 10, option C.

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