WAEC 2023 · Paper 1 · Q35

The angle of elevation of the top of a building from a point ZZ on the ground is 50∘50^\circ. If the height of the building is 124 m124\text{ m}, find the distance from ZZ to the foot of the building.

Worked solution (try it first)
  1. The height 124 m is opposite the 50∘50^\circ angle and the distance dd is adjacent, so tan⁡50∘=124d\tan50^\circ = \frac{124}{d}.
  2. Rearrange: d=124tan⁡50∘d = \frac{124}{\tan50^\circ}
    =1241.1918= \frac{124}{1.1918}.
  3. So d≈104.05d \approx 104.05 m, option A.

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