WAEC 2023 · Paper 1 · Q9

Find the roots of the equation 3m2−2m−65=03m^2 - 2m - 65 = 0.

Worked solution (try it first)
  1. Find two numbers with product 3×(−65)=−1953 \times (-65) = -195 and sum −2-2: they are −15-15 and 13.
  2. Split and group: 3m2−15m+13m−65=3m(m−5)+13(m−5)3m^2 - 15m + 13m - 65 = 3m(m - 5) + 13(m - 5)
    =(3m+13)(m−5)= (3m + 13)(m - 5).
  3. So m=5m = 5 or m=−133m = -\frac{13}{3}, option C.

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