WAEC 2023 · Paper 2 · Q4

  1. (a)

    The gradient of the line joining the points (−2,n)(-2, n) and (n,5)(n, 5) is 43\frac43. Find the value of nn.

  2. (b)

    Given that tan⁡x=158\tan x = \frac{15}{8}, 0∘<x<90∘0^\circ < x < 90^\circ, find the value of 5sin⁡x−6cos⁡x5\sin x - 6\cos x.

Worked solution (try it first)

(a)

  1. Gradient =5−nn−(−2)= \frac{5 - n}{n - (-2)}
    =5−nn+2= \frac{5 - n}{n + 2}
    =43= \frac43.
  2. Cross-multiply: 3(5−n)=4(n+2)3(5 - n) = 4(n + 2).
  3. So 15−3n=4n+815 - 3n = 4n + 8, 7n=77n = 7 and n=1n = 1.

(b)

  1. tan⁡x=158\tan x = \frac{15}{8}: the hypotenuse is 152+82=17\sqrt{15^2 + 8^2} = 17, so sin⁡x=1517\sin x = \frac{15}{17} and cos⁡x=817\cos x = \frac{8}{17}.
  2. Then 5sin⁡x−6cos⁡x=7517−48175\sin x - 6\cos x = \frac{75}{17} - \frac{48}{17}
    =2717= \frac{27}{17}.

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