WAEC 2024 · Paper 1 · Q2

Given that P={p:1<p<20}P = \{p : 1 < p < 20\}, where pp is an integer, and R={r:0≤r≤25R = \{r : 0 \le r \le 25, where rr is a multiple of 4}4\}, find P∩RP \cap R.

Worked solution (try it first)
  1. PP is the whole numbers strictly between 1 and 20: {2,3,…,19}\{2, 3, \dots, 19\}.
  2. RR is the multiples of 4 from 0 to 25: {0,4,8,12,16,20,24}\{0, 4, 8, 12, 16, 20, 24\}.
  3. The common elements are {4,8,12,16}\{4, 8, 12, 16\}, option B.
  4. (0 and 20 are not in PP.)

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