WAEC 2024 · Paper 1 · Q8LogarithmsIf log3(2x−1)=5\log_3(2x - 1) = 5log3(2x−1)=5, find the value of xxx.A8B16C64D122Worked solution (try it first)Change to index form: 2x−1=35=2432x - 1 = 3^5 = 2432x−1=35=243.Add 1: 2x=2442x = 2442x=244.Divide by 2: x=122x = 122x=122, option D.Report a problem with this question