WAEC 2024 · Paper 2 · Q11

  1. (a)

    Find the equation of the line that passes through the origin and the point of intersection of the lines x+2y=7x + 2y = 7 and x−y=4x - y = 4. (Give yy in terms of xx.)

  2. (b)

    The ratio of an interior angle to an exterior angle of a regular polygon is 4:14 : 1. Find the: (i) size of an exterior angle; (ii) number of sides; (iii) sum of the interior angles of the polygon.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. Find where the lines cross.
  2. Take x−y=4x - y = 4 from x+2y=7x + 2y = 7: 3y=33y = 3, so y=1y = 1 and x=4+1=5x = 4 + 1 = 5.
  3. The point is (5,1)(5, 1).
  4. The line passes through (0,0)(0, 0) and (5,1)(5, 1): gradient =1−05−0=15= \frac{1 - 0}{5 - 0} = \frac15.
  5. Through the origin, y=15xy = \frac15 x, that is x−5y=0x - 5y = 0.

(b)(i)

  1. Interior + exterior =180∘= 180^\circ, in the ratio 4:14 : 1 (5 parts).
  2. The exterior angle is one part: 180∘5=36∘\frac{180^\circ}{5} = 36^\circ.

(ii)

  1. Number of sides =360∘36∘=10= \frac{360^\circ}{36^\circ} = 10.

(iii)

  1. Sum of the interior angles =(10−2)×180∘=1440∘= (10 - 2) \times 180^\circ = 1440^\circ.

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