WAEC 2024 · Paper 2 · Q7

The table shows the ages of 20 children in a household.

Age (years) 5 6 7 8 9 10
Frequency 2 2x−12x - 1 y+2y + 2 4 2 y−1y - 1

Given that x:y=1:2x : y = 1 : 2, find the:

  1. (a)

    values of xx and yy;

    Separate values with commas, e.g. 3, −2

  2. (b)

    mean age of the children.

Worked solution (try it first)

(a)

  1. There are 20 children: 2+(2x−1)+(y+2)+4+2+(y−1)=202 + (2x - 1) + (y + 2) + 4 + 2 + (y - 1) = 20, so 8+2x+2y=208 + 2x + 2y = 20 and x+y=6x + y = 6.
  2. x:y=1:2x : y = 1 : 2 means y=2xy = 2x.
  3. Then x+2x=6x + 2x = 6, so x=2x = 2 and y=4y = 4.

(b)

  1. The frequencies are 2,3,6,4,2,32, 3, 6, 4, 2, 3 (total 20).
  2. ∑fx=5(2)+6(3)+7(6)+8(4)+9(2)+10(3)\sum fx = 5(2) + 6(3) + 7(6) + 8(4) + 9(2) + 10(3)
    =10+18+42+32+18+30= 10 + 18 + 42 + 32 + 18 + 30
    =150= 150.
  3. Mean age =15020=7.5= \frac{150}{20} = 7.5 years.

Report a problem with this question