WAEC 2025 · Paper 1 · Q18✱✱

Solve x+y=32x + y = \frac32 and x−y=52x - y = \frac52. Use your result to find 2y+x2y + x.

Worked solution (try it first)
  1. Add the two equations so yy cancels: 2x=32+52=42x = \frac32 + \frac52 = 4, so x=2x = 2.
  2. Put x=2x = 2 into x+y=32x + y = \frac32: y=32−2=−12y = \frac32 - 2 = -\frac12.
  3. So 2y+x=−1+2=12y + x = -1 + 2 = 1, option C.

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