WAEC 2025 · Paper 1 · Q40✱✱

In the diagram, AB∥CDAB \parallel CD. What is the size of the angle marked xx?

52°35°xABCD
Worked solution (try it first)
  1. Vertically opposite angles: ABAB also makes 52∘52^\circ with the upper line on the other side of the crossing.
  2. CD∥ABCD \parallel AB, so CDCD makes the same 52∘52^\circ with the upper line (corresponding angles).
  3. This angle is inside the small triangle cut off by CDCD at the 35∘35^\circ vertex.
  4. The angles of that triangle add up to 180∘180^\circ: x=180∘−52∘−35∘x = 180^\circ - 52^\circ - 35^\circ
    =93∘= 93^\circ, option A.

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