WAEC 2025 · Paper 1 · Q48✱✱

Two fair dice are tossed once. Find the probability that the sum is at least 10.

Worked solution (try it first)

Two dice give 36 equally likely outcomes.
A sum of at least 10 comes from $(4, 6), (5, 5), (6, 4), (5, 6), (6, 5), (6, 6)$ , which is 6 outcomes.
So the probability is $\frac{6}{36} = \frac16$ , option A.