WAEC 2025 · Paper 1 · Q5✱✱

Given that $\log_2 a = \log_8 4$ , find $a$ .

Worked solution (try it first)

Find $\log_8 4$ : $8 = 2^3$ and $4 = 2^2$ , so $8^{\frac23} = 2^2 = 4$ and $\log_8 4 = \frac23$ .
So $\log_2 a = \frac23$ .
Change to index form: $a = 2^{\frac23}$ , option B.