Flashcards · 13 cards

Sequences, series & binomial expansion

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  1. Rule

    The nnth term and the sum of nn terms of an A.P.?

    Answer

    Tn=a+(n−1)dT_n = a + (n - 1)d and Sn=n2[2a+(n−1)d]S_n = \dfrac n2[2a + (n - 1)d].

    a + ln terms
    Sum of an A.P.Sₙ = n/2 [2a + (n − 1)d]
  2. Know it

    "How much in the 16th week?" and "how much in 16 weeks?": which is which?

    Answer

    The first is a term, T16T_{16}. The second is a sum, S16S_{16}.

  3. Rule

    The least number of terms for the sum to pass 90?

    Answer

    The first nn where SnS_n goes past 90: S7=77<90<100=S8S_7 = 77 < 90 < 100 = S_8, so n=8n = 8. Solve the inequality, then round up.

    target 90123456789S₈ = 100
    First past the targetS₇ = 77 < 90 < 100 = S₈: least n is 8
  4. Rule

    un+2=un+1+2unu_{n + 2} = u_{n + 1} + 2u_n, with u1=u2=1u_1 = u_2 = 1. Find u3u_3.

    Answer

    Build each term from the ones before: u3=u2+2u1=1+2=3u_3 = u_2 + 2u_1 = 1 + 2 = 3.

    1T11T23T35T411T5each term = the one before + 2 × the one before that
    Each term from the ones beforeu₃ = u₂ + 2u₁ = 1 + 2 = 3, and so on
  5. Rule

    The nnth term, the sum of nn terms and the sum to infinity of a G.P.?

    Answer

    Tn=arn−1T_n = ar^{n - 1}, Sn=a(rn−1)r−1S_n = \dfrac{a(r^n - 1)}{r - 1}, and S∞=a1−rS_\infty = \dfrac{a}{1 - r} when −1<r<1-1 < r < 1.

    aarar²S∞never quite reaches the end
    Sum to infinityS∞ = a ÷ (1 − r), when −1 < r < 1
  6. Rule

    Three consecutive terms of a G.P. with a known product: what do you call them?

    Answer

    ar\dfrac ar, aa and arar. Their product is a3a^3, so aa comes out at once.

    a ÷ raar× r× rproduct: (a ÷ r) × a × ar = a³
    Three consecutive termsThe product is a³, so a comes out at once
  7. Know it

    r2=9r^2 = 9. What is rr?

    Answer

    r=3r = 3 or r=−3r = -3. Use the question's condition, such as "r>0r > 0", to choose.

  8. Rule

    The coefficients of (a+b)5(a + b)^5?

    Answer

    Row 5 of Pascal's triangle: 1,5,10,10,5,11, 5, 10, 10, 5, 1, that is 5C0,…,5C5{}^5C_0, \dots, {}^5C_5.

    01111212131331414641515101051row n gives the coefficients of (a + b)ⁿ
    Pascal's triangleRow 5: 1, 5, 10, 10, 5, 1 are ⁵C₀ … ⁵C₅
  9. Rule

    The (r+1)(r + 1)th term of (a+b)n(a + b)^n?

    Answer

    nCr an−rbr{}^nC_r\, a^{n - r} b^r: the powers always add up to nn.

    term r + 1 = ⁿCᵣ aⁿ⁻ʳ bʳ(2 − x)⁵, term 3, so r = 2:⁵C₂ × 2³ × (−x)² = 10 × 8x² = 80x²
    The (r + 1)th termⁿCᵣ aⁿ⁻ʳ bʳ: the powers always add up to n
  10. Rule

    (1+x)n(1 + x)^n when nn is a fraction or negative?

    Answer

    1+nx+n(n−1)2!x2+n(n−1)(n−2)3!x3+…1 + nx + \dfrac{n(n - 1)}{2!}x^2 + \dfrac{n(n - 1)(n - 2)}{3!}x^3 + \dots, valid only for ∣x∣<1|x| < 1. Write each coefficient out; don't use nCr{}^nC_r.

    xy−11|x| < 1√(1 + x)1 + ½x − ⅛x²
    Close only for small x√(1 + x) and its first three terms agree inside |x| < 1 and pull apart outside it
  11. Which method?

    WAEC 2019 · Paper 2 · Q3

    How many terms of the series −3−1+1+…-3 - 1 + 1 + \ldots add up to 165?

    How do you find how many terms add up to 165?

    Answer

    With a=−3a = -3 and d=2d = 2, Sn=n2[−6+2(n−1)]=n(n−4)S_n = \frac n2[-6 + 2(n - 1)] = n(n - 4). Set n(n−4)=165n(n - 4) = 165 and keep the positive whole-number solution.

  12. Which method?

    WAEC 2018 · Paper 2 · Q3

    The sum of the second and third terms of a Geometric Progression (G.P.) is 48. If the sum of the third and fourth terms is 144, find the first term of the progression.

    How do you find rr first?

    Answer

    Factorise each fact: ar(1+r)=48ar(1 + r) = 48 and ar2(1+r)=144ar^2(1 + r) = 144. Divide the second by the first: r=3r = 3.

  13. Which method?

    WAEC 2011 · Paper 2 · Q3

    Write down the binomial expansion of (2−x)5(2 - x)^5 in ascending powers of xx.

    Use your expansion in (a) to evaluate (1.98)5(1.98)^5 correct to four decimal places.

    Which value of xx gives 1.9851.98^5 from the expansion of (2−x)5(2 - x)^5?

    Answer

    Solve 2−x=1.982 - x = 1.98: x=0.02x = 0.02. Put it into the expansion and round to the accuracy asked.