Flashcards · 10 cards

Matrices & linear transformations

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  1. Rule

    How do you multiply two matrices?

    Answer

    Across the row of the first, down the column of the second, multiplying in pairs and adding. ABAB and BABA are usually different.

    abcdpqrs=•• = ap + br
    Row times columnMultiply across the row and down the column, then add
  2. Rule

    The inverse of (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix}?

    Answer

    1ad−bc(d−b−ca)\dfrac{1}{ad - bc}\begin{pmatrix} d & -b \\ -c & a \end{pmatrix}. No inverse when ad−bc=0ad - bc = 0.

    A⁻¹ =1ad − bcd−b−caswap a, d · change signs of b, c
    The inverseA⁻¹ = (1 ÷ (ad − bc)) × (d, −b / −c, a)
  3. Know it

    How do you solve two simultaneous equations with a matrix?

    Answer

    Write them as A(xy)=(pq)A\begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} p \\ q \end{pmatrix}. Then (xy)=A−1(pq)\begin{pmatrix} x \\ y \end{pmatrix} = A^{-1}\begin{pmatrix} p \\ q \end{pmatrix}.

  4. Rule

    A 3×33 \times 3 determinant along the top row?

    Answer

    a(ei−fh)−b(di−fg)+c(dh−eg)a(ei - fh) - b(di - fg) + c(dh - eg): signs +  −  ++\;-\;+, each entry times the 2×22 \times 2 left when you cover its row and column.

    abcdefghi+−+a(ei − fh)− b(di − fg)+ c(dh − eg)
    Along the top rowa(ei − fh) − b(di − fg) + c(dh − eg)
  5. Rule

    Cramer's rule?

    Answer

    x=ΔxΔx = \dfrac{\Delta_x}{\Delta}, y=ΔyΔy = \dfrac{\Delta_y}{\Delta}, z=ΔzΔz = \dfrac{\Delta_z}{\Delta}, where Δx\Delta_x is Δ\Delta with its xx-column replaced by the right-hand sides.

    Δxpbcqefrhix = Δx ÷ Δp, q, r goin column x
    Cramer's rulex = Δx ÷ Δ, y = Δy ÷ Δ, z = Δz ÷ Δ
  6. Rule

    What do the columns of a transformation matrix tell you?

    Answer

    Column 1 is the image of (1,0)(1, 0); column 2 is the image of (0,1)(0, 1).

    (a, c)(b, d)columns of(a b / c d)
    What the columns mean(1, 0) → (a, c) and (0, 1) → (b, d)
  7. Rule

    The matrix of a rotation through θ\theta anticlockwise about OO?

    Answer

    (cos⁡θ−sin⁡θsin⁡θcos⁡θ)\begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}. Test it on (1,0)(1, 0): the image must be (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta).

    θθiji′j′cos θ−sin θsin θcos θi′j′anticlockwise θ
    Rotation through θi′ = (cos θ, sin θ) is column 1, j′ = (−sin θ, cos θ) is column 2
  8. Rule

    The single matrix for "NN followed by MM"?

    Answer

    MNMN: the transformation applied first goes on the right.

    PN firstNPthen MMNP"N followed by M" = MNN acts first, on the right
    N followed by MThe combined matrix is MN
  9. Which method?

    WAEC 2019 · Paper 2 · Q11

    Given that M:(x,y)→(7y,3x−y)M : (x, y) \to (7y, 3x - y) and N:(x,y)→(2x−y,5x+3y)N : (x, y) \to (2x - y, 5x + 3y),

    write down the matrices MM and NN of the linear transformations;

    find the image of P(2,−3)P(2, -3) under the linear transformation NN followed by MM;

    find the coordinates of the point QQ whose image is Q′(2,4)Q'(2, 4) under the linear transformation NN.

    How do you write MM and NN, and which product gives "NN followed by MM"?

    Answer

    Read the coefficients of each rule row by row: M=(073−1)M = \begin{pmatrix} 0 & 7 \\ 3 & -1 \end{pmatrix}. Then use MNMN, with NN (applied first) on the right.

  10. Which method?

    WAEC 2020 · Paper 2 · Q11 (a)

    Find the positive value of yy for which ∣y101y101y∣=0\begin{vmatrix} y & 1 & 0 \\ 1 & y & 1 \\ 0 & 1 & y \end{vmatrix} = 0 (4 d.p.).

    How do you expand this determinant?

    Answer

    Along the top row: y(y2−1)−1(y−0)+0=y3−2yy(y^2 - 1) - 1(y - 0) + 0 = y^3 - 2y. Set that to 0 and solve.