Flashcards · 14 cards

Sequences & series (AP, GP)

Say the answer to yourself, then check. Cards you know come back less and less often; cards you don't come back tomorrow.

  1. Rule

    The nnth term of an A.P.?

    Answer

    Tn=a+(n−1)dT_n = a + (n - 1)d, where aa is the first term and dd the common difference.

    aT1adT2addT3adddT4addddT5
    nth term of an A.P.Tₙ = a + (n − 1)d: T₅ has 4 blocks of d
  2. Know it

    What is the common difference of 20,17,14,…20, 17, 14, \dots?

    Answer

    Second term minus first: 17−20=−317 - 20 = -3.

  3. Rule

    xx, yy and zz are consecutive terms of an A.P. What is true?

    Answer

    y−x=z−yy - x = z - y, so 2y=x+z2y = x + z.

    xyz+d+d
    Consecutive terms of an A.P.y − x = z − y, so 2y = x + z
  4. Know it

    How do you check a formula for the nnth term?

    Answer

    Test it on at least three terms. Many formulas fit the first two.

  5. Rule

    The sum of the first nn terms of an A.P.?

    Answer

    Sn=n2(a+l)S_n = \dfrac n2(a + l) when you know the last term ll, or Sn=n2[2a+(n−1)d]S_n = \dfrac n2\big[2a + (n - 1)d\big].

    a + ln terms
    Sum of an A.P.Two copies make n columns of a + l, so Sₙ = n/2 (a + l)
  6. Know it

    How many terms are there in 2+5+8+⋯+622 + 5 + 8 + \dots + 62?

    Answer

    Use the nnth term, not the last number: 2+(n−1)×3=622 + (n - 1) \times 3 = 62, so n=21n = 21.

  7. Rule

    The nnth term of a G.P.?

    Answer

    Tn=arn−1T_n = ar^{n - 1}: only rr is raised to the power. For 3,6,12,…3, 6, 12, \dots, T6=3×25=96T_6 = 3 \times 2^5 = 96.

    aar×rar²×rar³×r
    nth term of a G.P.Tₙ = arⁿ⁻¹: each bar is r times the one before
  8. Rule

    xx, yy and zz are consecutive terms of a G.P. What is true?

    Answer

    yx=zy\dfrac yx = \dfrac zy, so y2=xzy^2 = xz.

    xyz×r×r
    Consecutive terms of a G.P.y ÷ x = z ÷ y, so y² = xz
  9. Know it

    r2=4r^2 = 4. What is rr?

    Answer

    r=2r = 2 or r=−2r = -2. An even power gives two values; r3=8r^3 = 8 gives only r=2r = 2.

  10. Rule

    The sum of the first nn terms of a G.P.?

    Answer

    Sn=a(rn−1)r−1S_n = \dfrac{a(r^n - 1)}{r - 1}.

    S=a+ ar+ ar²+ …+ arⁿ⁻¹rS=ar+ ar²+ …+ arⁿ⁻¹+ arⁿthe same in both rows: they cancel
    Sum of a G.P.rS − S = arⁿ − a, so Sₙ = a(rⁿ − 1) ÷ (r − 1)
  11. Rule

    The sum to infinity of a G.P.? When does it exist?

    Answer

    S∞=a1−rS_\infty = \dfrac{a}{1 - r}, only when −1<r<1-1 < r < 1.

    aarar²S∞never quite reaches the end
    Sum to infinityWith r = ½ each piece is half the gap left: S∞ = a ÷ (1 − r)
  12. Which method?

    WAEC 2022 · Paper 2 · Q1

    The third term of an Arithmetic Progression (A.P.) is 23 and the sum of the first seven terms is 210. Find the:

    common difference;

    first term;

    sum of the first 20 terms.

    How do you turn each fact into an equation?

    Answer

    The third term is one term: a+2d=23a + 2d = 23. The sum of seven terms is a sum: 72[2a+6d]=210\frac72[2a + 6d] = 210. Solve the two together.

  13. Which method?

    WAEC 2024 · Paper 2 · Q6

    Given that (x+2)(x + 2), (4x+3)(4x + 3) and (7x+24)(7x + 24) are consecutive terms of a geometric progression (G.P.), find the:

    values of xx;

    common ratio (for each value of xx).

    What equation links the three terms?

    Answer

    In a G.P. the ratios are equal: 4x+3x+2=7x+244x+3\dfrac{4x + 3}{x + 2} = \dfrac{7x + 24}{4x + 3}. Cross-multiply to get a quadratic.

  14. Which method?

    JAMB 1999 · UME · Q12

    The first term of a geometric progression is twice its common ratio. Find the sum of the first two terms of the progression if its sum to infinity is 8.

    How do you use "the first term is twice its common ratio"?

    Answer

    Write a=2ra = 2r and put it into S∞=a1−r=8S_\infty = \dfrac{a}{1 - r} = 8. That leaves one unknown, rr.