Flashcards · 18 cards

Angles, triangles & polygons

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  1. Rule

    Angles on a straight line add up to what?

    Answer

    180∘180^\circ.

    ab
    On a straight linea + b = 180°
  2. Rule

    Angles at a point add up to what?

    Answer

    360∘360^\circ.

    abc
    At a pointa + b + c = 360°
  3. Rule

    Vertically opposite angles are…?

    Answer

    Equal.

    aabb
    Vertically oppositeThe two a's are equal, and so are the two b's
  4. Rule

    Corresponding angles on parallel lines are…?

    Answer

    Equal (they sit in an F shape).

    aa
    CorrespondingEqual
  5. Rule

    Alternate angles on parallel lines are…?

    Answer

    Equal (they sit in a Z shape).

    aa
    AlternateEqual
  6. Rule

    Co-interior angles on parallel lines…?

    Answer

    Add up to 180∘180^\circ (a C shape). They are not equal.

    ba
    Co-interiora + b = 180°
  7. Rule

    A bend between two parallel lines: how do you find the angle at the corner?

    Answer

    Draw a third parallel through the corner. The corner angle splits into two alternate angles: it is a+ba + b.

    aabb
    A bend between parallelsDraw a parallel through the corner: the corner angle is a + b
  8. Rule

    The angles of a triangle add up to what?

    Answer

    180∘180^\circ.

    abc
    Angle suma + b + c = 180°
  9. Rule

    The exterior angle of a triangle equals…?

    Answer

    The sum of the two interior angles opposite it (not the one next to it).

    aba + b
    Exterior angleThe exterior angle is a + b
  10. Rule

    In an isosceles triangle, which angles are equal?

    Answer

    The two angles facing the equal sides (the base angles).

    xx
    Isosceles triangleEqual sides (ticks) face equal angles
  11. Rule

    The interior angles of an nn-sided polygon add up to what?

    Answer

    (n−2)×180∘(n - 2) \times 180^\circ. A pentagon: 3×180∘=540∘3 \times 180^\circ = 540^\circ.

    123
    Interior anglesA pentagon is 3 triangles: (5 − 2) × 180° = 540°
  12. Rule

    The exterior angles of a polygon add up to what?

    Answer

    360∘360^\circ, for every polygon. For a regular one, n=360∘exterior anglen = \dfrac{360^\circ}{\text{exterior angle}}.

    Exterior anglesThey add up to 360° for every polygon
  13. Know it

    Each interior angle of a regular polygon is 144∘144^\circ. How many sides does it have?

    Answer

    Find the exterior angle first: 180∘−144∘=36∘180^\circ - 144^\circ = 36^\circ. Then n=360÷36=10n = 360 \div 36 = 10.

  14. Rule

    Pythagoras' theorem?

    Answer

    c2=a2+b2c^2 = a^2 + b^2, where cc is the hypotenuse, opposite the right angle. For a shorter side, subtract: a2=c2−b2a^2 = c^2 - b^2.

    abc
    Pythagorasc is opposite the right angle: c² = a² + b²
  15. Rule

    The four tests for congruent triangles?

    Answer

    SSS, SAS (the angle between the two sides), ASA and RHS.

    SASTwo sides and the angle between them
  16. Rule

    Similar triangles: how are the sides and the areas related?

    Answer

    The angles are the same. Every side is multiplied by the same kk, and the area by k2k^2. Match corners by their equal angles before pairing sides.

    akabkb
    Similar trianglesSame angles; every side × k; area × k²
  17. Which method?

    WAEC 2022 · Paper 2 · Q11 (a)

    The exterior angles of a polygon are 42∘,38∘,57∘,x∘,(x+y)∘,(2x−15)∘42^\circ, 38^\circ, 57^\circ, x^\circ, (x + y)^\circ, (2x - 15)^\circ and (3x−y)∘(3x - y)^\circ. If xx is 7∘7^\circ less than yy, find the values of xx and yy.

    Which fact do you use?

    Answer

    The exterior angles of any polygon add up to 360∘360^\circ. Add them all, set the total to 360, and the yy terms cancel.

  18. Which method?

    WAEC 2014 · Paper 2 · Q3 (a)

    In the diagram, QSPQSP and QTRQTR are straight lines, ∣PS∣=6 cm|PS| = 6\text{ cm}, ∣QS∣=4 cm|QS| = 4\text{ cm}, ∣QT∣=5 cm|QT| = 5\text{ cm} and ∠QTS=∠RPQ\angle QTS = \angle RPQ. Calculate ∣TR∣|TR|.

    4 cm6 cm5 cmQTRSP
    Which triangles are similar, and how do you pair the sides?

    Answer

    Triangles QTSQTS and QPRQPR share the angle at QQ and have ∠QTS=∠QPR\angle QTS = \angle QPR. So TT matches PP and SS matches RR: QTQP=QSQR\dfrac{QT}{QP} = \dfrac{QS}{QR}, using whole sides.