Flashcards · 7 cards

Longitude & latitude

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  1. Rule

    What is latitude?

    Answer

    The angle at the centre of the earth between a place and the equator, north or south: 0∘0^\circ to 90∘90^\circ.

    POθNequatorlatitude θ°N
    Latitude θ: the angle at the centre O between OP and the equator
  2. Rule

    What is longitude?

    Answer

    The angle east or west of the Greenwich meridian: 0∘0^\circ to 180∘180^\circ.

    North PoleGreenwich 0°φQEastWest180°
    Longitude φ: the angle east or west of the Greenwich meridian
  3. Know it

    Two places are at 35∘35^\circE and 25∘25^\circW. What is their difference in longitude?

    Answer

    35∘+25∘=60∘35^\circ + 25^\circ = 60^\circ: they are on opposite sides of Greenwich, so add. Same side: subtract.

  4. Know it

    The distance between two places on the same meridian?

    Answer

    difference in latitude360×2πR\dfrac{\text{difference in latitude}}{360} \times 2\pi R, where RR is the radius of the earth. A meridian is a great circle.

  5. Know it

    The radius of the circle of latitude θ\theta?

    Answer

    Rcos⁡θR\cos\theta. It gets smaller towards the poles.

  6. Rule

    The distance between two places on the same latitude θ\theta?

    Answer

    difference in longitude360×2πRcos⁡θ\dfrac{\text{difference in longitude}}{360} \times 2\pi R\cos\theta. Only the equator has the full radius RR.

    North PoleSouth PoleEquator 0°30°N60°N30°SGreenwichmeridian 0°
    Parallels of latitude run east–west and shrink towards the poles; meridians run from pole to pole
  7. Which method?

    WAEC 2013 · Paper 2 · Q12

    An aeroplane flies due north from a town TT on the equator at a speed of 950 km950\text{ km} per hour for 4 hours to another town PP. It then flies eastwards to town QQ on longitude 65∘65^\circE. If the longitude of TT is 15∘15^\circE, (i) represent this information in a diagram; (ii) calculate the: (I) latitude of PP, correct to the nearest degree; (II) distance between PP and QQ, correct to 4 significant figures. [Take π=227, radius of the earth=6400 km]\left[\text{Take }\pi = \frac{22}{7}, \text{ radius of the earth} = 6400\text{ km}\right]

    Flying due north for 4 hours covers 3800 km. How do you find the new latitude?

    Answer

    Due north is along a meridian, a great circle of radius RR: θ360×2πR=3800\dfrac{\theta}{360} \times 2\pi R = 3800 gives the change in latitude θ\theta.