JAMB 1983 · UME · Q25

Quadratics & their graphs

Find the missing value for $x = -2$ in a table of values of $y = x^3 - x + 3$ .

Worked solution (try it first)

Put $x = -2$ into $y = x^3 - x + 3$ .
The cube of a negative is negative: $(-2)^3 = -8$ .
Subtracting $-2$ adds 2.
So $y = -8 + 2 + 3 = -3$ , option A.

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