JAMB 1983 · UME · Q26

If OO is the centre of the circle in the figure, find the value of xx.

130°x°OABC
Worked solution (try it first)
  1. CC is on the minor arc, so ∠ACB=130∘\angle ACB = 130^\circ stands on the major arc ABAB.
  2. The angle at the centre is twice the angle at the circumference, so the reflex angle AOBAOB is 2×130∘=260∘2 \times 130^\circ = 260^\circ.
  3. Angles at a point add up to 360∘360^\circ, so x=360∘−260∘=100∘x = 360^\circ - 260^\circ = 100^\circ, option C.

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